Question

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Answer 1

hola

∆ Resolviendo :

${(2x - 4)}^{2} - 1 = 3$

${(2x)}^{2} - 2.2x.4 + {4}^{2} - 1 = 3$

$4 {x}^{2} - 16x + 16 - 1 = 3$

$4 {x}^{2} - 16x + 15 = 3$

$4 {x}^{2} - 16x = 3 - 15$

$4x(x - 4) = - 12$

___________________

X1 → 4x = -12

x = -12/4

x = -3

____________

x2 → x -4 = -12

x = -12+4

x = -8

Solución → ( -3 : -8)

Saludos y buen día