Question

ayudaa es de factor común<3​

Answer 1

Explicación paso a paso:

1.

$4 {x}^{3} - 2x = x(4 {x}^{2} - 2)$

2.

$6{y}^{5} + 3y = y(6 {y}^{4} + 3)$

3.

$10 {x}^{4} - 5 {x}^{2} = {x}^{2} (10 {x}^{2} - 5)$

4.

$15 {y}^{6} + 3 {y}^{3} = {y}^{3} (15 {y}^{3} + 3)$

5.

$20 {x}^{4} - 4 {x}^{2} = {x}^{2} (20 {x}^{2} - 4)$

6.

$8 {y}^{3} + 2y = y(8 {y}^{2} + 2)$