Question

ayuda porfavorrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

Answer 1

Respuesta:

1012

Explicación paso a paso:

*Dato:

$\begin{bmatrix}A\end{bmatrix}=2A^{2}-5$

*Desarrollando:

$\begin{bmatrix}2\end{bmatrix}=2(2^{2})-5=3$

$\begin{bmatrix}3\end{bmatrix}=2(3^{2})-5=13$

Ahora

$V=\begin{bmatrix}\begin{bmatrix}2\end{bmatrix}\end{bmatrix}+3\begin{bmatrix}\begin{bmatrix}3\end{bmatrix}\end{bmatrix}$

$V=\begin{bmatrix}3\end{bmatrix}+3\begin{bmatrix}13\end{bmatrix}$

$V=13+3(2(13^{2})-5)$

$V=13+3(338-5)$

$V=13+3(333)$

$V=13+999$

$V=1012$