Question

AYUDA..........PORFAVOR

Answer 1

Respuesta:

Explicación paso a paso:

EJERCICIO A

$37x^2+4m-27x^2+15m\\\\=37x^2-27x^2+4m+15m\\\\=37x^2-27x^2+19m\\\\=10x^2+19m$

EJERCICIO B

$\frac{3}{2}x^2+\frac{4}{5}x-\frac{6}{3}x^2+\frac{1}{5}x$

$=\frac{3}{2}x^2-\frac{6}{3}x^2+\frac{4}{5}x+\frac{1}{5}x\\\\=-\frac{1}{2}x^2+\frac{4}{5}x+\frac{1}{5}x\\\\=-\frac{1}{2}x^2+\frac{4}{5}x+\frac{1}{5}x\\\\=-\frac{x^2}{2}+x$

SALUDOS

Answer 2

Explicación paso a paso:

a)

$37 {x}^{2} + 4m - 27 {x}^{2} + 15m =$

Agrupamos términos semejantes:

$37 {x}^{2} - 27 {x}^{2} + 4m + 15m =$

$10 {x}^{2} + 19m =$

b)

$\frac{3}{2} {x}^{2} - \frac{4}{5} x + \frac{6}{3} {x}^{2} - \frac{1}{5} x =$

Agrupamos términos semejantes:

$( \frac{3}{2} + \frac{6}{3} ) {x}^{2} - ( \frac{4}{5} + \frac{1}{5} )x =$

$\frac{21}{6} {x}^{2} - \frac{5}{5}x =$

$\frac{7}{2} {x}^{2} - x =$