Question

ayuda plis ........ ​

Answer 1

RESOLVER:

a) $\left(5x^2+6\right)-\left(3x^2+8\right)$

$\left(5x^2+6\right)=5x^2+6\\\\=5x^2+6-\left(3x^2+8\right)\\\\-\left(3x^2+8\right)=-3x^2-8\\\\=5x^2+6-3x^2-8\\\\=5x^2-3x^2+6-8\\\\=5x^2-3x^2-2\\\\\boxed{=2x^2-2}$

b) $\left(7x^3-2x^2+6\right)-\left(7x^2+2x-4\right)$

$\left(7x^3-2x^2+6\right)=7x^3-2x^2+6\\\\=7x^3-2x^2+6-\left(7x^2+2x-4\right)\\\\-\left(7x^2+2x-4\right)=-7x^2-2x+4\\\\=7x^3-2x^2+6-7x^2-2x+4\\\\=7x^3-2x^2-7x^2-2x+6+4\\\\=7x^3-2x^2-7x^2-2x+10\\\\\boxed{=7x^3-9x^2-2x+10}$

c) $\left(6x^3-3x^2+x+1\right)-\left(8x^3+3x^2-1\right)$

$\left(6x^3-3x^2+x+1\right)=6x^3-3x^2+x+1\\\\=6x^3-3x^2+x+1-\left(8x^3+3x^2-1\right)\\\\-\left(8x^3+3x^2-1\right)=-8x^3-3x^2+1\\\\=6x^3-3x^2+x+1-8x^3-3x^2+1\\\\=6x^3-8x^3-3x^2-3x^2+x+1+1\\\\=6x^3-8x^3-3x^2-3x^2+x+2\\\\=-2x^3-3x^2-3x^2+x+2\\\\\boxed{=-2x^3-6x^2+x+2}$

d) $\left(3x^3-4x^2-5x\right)+\left(5x^3+2x-3x\right)$

$=3x^3-4x^2-5x+5x^3+2x-3x\\\\=3x^3+5x^3-4x^2-5x+2x-3x\\\\=8x^3-4x^2-5x+2x-3x\\\\\boxed{=8x^3-4x^2-6x}$

MUCHA SUERTE...