Question

ayuda lo neseito doy coronita

Answer 1

Primera hoja :

$(\frac{3}{5}) ^{4} = \frac{81}{625}$

$(-\frac{9}{2} )^{0} = 1$

$(-\frac{2}{3})^{5} = -\frac{32}{243}$

$(-\frac{8}{3})^{2} = -\frac{64}{9}$

Segunda hoja :

$(\frac{2}{3})^{2} .(\frac{2}{3} )^{2} = \frac{4}{9} . \frac{4}{9} = \frac{16}{81}$

$(\frac{5}{3})^{2} .(\frac{5}{3})^{2} = \frac{25}{9} . \frac{25}{9} = \frac{625}{81}$

$(\frac{4}{5})^{10} .(\frac{4}{5})^{7} = (\frac{4}{5})^{10-7} = (\frac{4}{5})^{3} = \frac{64}{125}$

$[(\frac{1}{2})^{2}]^{3} = (\frac{1}{2})^{2.3} = (\frac{1}{2})^{6}= \frac{1}{64}$

$(\frac{4}{3})^{-5} = (\frac{3}{4})^{5} = \frac{243}{1024}$

:)