Question

Ayuda a derivar porvafor

y=xsenx cosx
U V
y=(x^2+4x+6)^5

Answer 1

y = (x² + 4x + 6)^5
y' = 5 (x² + 4x + 6)^4  (2x + 4)

y = x senx cosx = U´ V + U V¨
y' = senx ( x cosx) (cosx) + x senx (- senx)
y' = x senx cos²x -  xsen²x
y' = x senx (cos²x - senx)