Question

Alguien que lo resuelva doy puntos

Answer 1

Respuesta:

$\sqrt{-3,9"x} -5,9"=4\\\\\sqrt{-\frac{39-3}{90}.x } -\frac{59-5}{90}= 4$

$\sqrt{-\frac{36}{90}.x }-\frac{54}{90}=4$

$\sqrt{-\frac{2}{5} x}-\frac{3}{5}=4$

$\sqrt{-\frac{2}{5} .x}= 4+\frac{3}{5}$

$\sqrt{-\frac{2}{5}.x} =\frac{4.5+3}{5}$

$\sqrt{-\frac{2x}{5} }= \frac{23}{5}$

$-\frac{2x}{5}=(\frac{23}{5}) ^{2}$

$-\frac{2x}{5}=\frac{529}{25}$

$-\frac{2x}{1}=\frac{529}{5}$

-2x.5=529

-10x=529

x= -52,9