Question

alguien me ayuda es radicales es lineal pord
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Answer 1

Respuesta:

√(8y+9)-√(18y+34)+√(2y+7) = 0

√(8y+9)-√(18y+34)+√(2y+7)+√(18y+34) = 0+√(18y+34)

√(8y+9)+√(2y+7) = √(18y+34)

√(8y+9)+√(2y+7)-√(2y+7) = √(18y+34)-√(2y+7)

√(8y+9) = √(18y+34)-√(2y+7)

(√(8y+9))² = (√(18y+34)-√(2y+7))²

8y+9 = (√(18y+34))²-2((√(18y+34))(√(2y+7)))+(√(2y+7))²

8y+9 = 18y+34-2((√((18y+34)(2y+7))+2y+7

8y+9 = (18+2)y+(34+7)-2(√((18y)(2y+7)+34(2y+7))

8y+9 = 20y+41-2√(36y²+126y+68y+238)

8y+9 = 20y+41-2√(36y²+194y+238)

8y+9-20y-41 = -2√(36y²+194y+238)

(8-20)y+(9-41) = -2√(36y²+194y+238)

-12y+(-32) = -2√(36y²+194y+238)

-12y-32 = -2√(36y²+194y+238)

-(-12y-32) = -(-2√(36y²+194y+238))

12y+32 = 2√(36y²+194y+238)

(12y+32)/2 = 2√(36y²+194y+238)/2

(12/2)y+(32/2) = (2/2)√(36y²+194y+238)

6y+16 = √(36y²+194y+238)

(6y+16)² = (√(36y²+194y+238))²

(6y)²+2((6y)(16))+(16)² = 36y²+194y+238

36y²+2(96y)+256 = 36y²+194y+238

36y²+192y+256 = 36y²+194y+238

36y²+192y+256-36y² = 36y²+194y+238-36y²

192y+256 = 194y+238

192y+256-192y = 194y+239-192y

(192-192)y+256 = (194-192)y+238

256 = 2y+238

256-238 = 2y+238-238

18 = 2y

2y = 18

(2/2)y = 18/2

y = 9

Verificación :

√(8(9)+9)-√(18(9)+34)+√(2(9)+7) = 0

√(72+9)-√(162+34)+√(18+7) = 0

√(81)-√(196)+√(25) = 0 ; √(81) = 9

9-√(196)+√(25) = 0 ; √(196) = 14

9-14+√(25) = 0

- 5+√(25) = 0 ; √(25) = 5

- 5+(5) = 0

- 5+5 = 0

0 = 0

R// Por ende , el valor de la incógnita " y " en esa ecuación con radicales es 9 .

Espero haberte ayudado .

Saludos .