Química, pregunta formulada por lakshmilakshmi29065, hace 1 mes

A stone is tied to one end of string and whirled in a horizontal circle of a radius 1m at 20 revolutions. per minute calculate the angular velocity an linear speed of the stone also find the centripetal acceleration​

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Contestado por lumar173
1

Calculating linear velocity and centripetal acceleration for a stone tied to one end of a string and whirled in a circle, the results are:

linear velocity = 0,333 m/s

centripetal acceleration = 0,1111 m/s²

Explanation:

r = 1 m

angular velocity = ω = 20 revolutions/min = 20 rpm

linear speed = v = ?

centripetal acceleration = ac = ?

We know:

lenght of string = l = 1 m = r

ω = 20 revolutions/min

Thus, we calculate v:

v =  ω × r        

v = 20 × 1 m = 20 m/min

v = 20 m/min × 1 min/60 s = 0,333 m/s

linear velocity = 0,333 m/s

Then, we can calculate the centripetal acceleration, given by the equation:

ac = v² / r

ac = (0,333 m/s)² / 1 m )

ac = 0,1111 m/s²

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