Question

4x^+6×=-130 fórmula general, tabla y grafica

Answer 1

Delia,
Vamos paso a paso

La ecuación
                     4x^2 + 6x + 130 = 0

Aplicando la fórmula resolutoria
                     x = (- b +/- √D)/2a
                                                     D = b^2 - 4.a.c

                                                         = 6^2 - 4(4)(130)
                                                         = 36 - 2080
                                                     D = - 2044
                                                      D negativo:
                                                              dos raices complejas diferentes
                 x = (- 6 +/- √(-2044)/8
                    = (- 6 +/- 2√-511)8
                    = (- 3 +/- √511i)/4

                 x1 = (- 3 - √511i)/4
                 x2 = (- 3 + √511i)/4

                                        S = {(- 3 - √511i)/4 , (- 3 + √511i)/4}