Question

3(3x-2)=(x+4)(4-x)
Ayudaaaaa!!!!

Answer 1

9x-6=4x-x^2+16-4x
9x-6-4x+x^2-16+4x=0
x^2+9x-16=0

hacemos la e. de 2º grado
x1=-10.52
x2=1.52

Answer 2

3(3x-2) = (x+4)(4-x)
9x - 6 = 4x -x² + 16 - 4x
9x - 6 = 16 - x²
x²+9x = 16+6
x²+9x-22 = 0

x = {-9+-√(9² - (4*1*-22))} / 2.1
x = {-9+-√(81+88)} / 2
x = {-9+-√169} / 2
x = {-9+-13} / 2
x₁ = {-9-13}/2 = -22/2 = -11
x₂ = {-9+13}/2 = 4/2 = 2

Comprobación:
3((3*2)-2) = (2+4)(4-2)
18-6 = 6*2
12 = 12

3((3*-11)-2) = (-11+4)(4-(-11))
-99-6 = -7*15
-105 = -105

Respuesta:
x₁ = -11
x₂ = 2