Question

23X/20+4X-13/15=7X/5+4X-5/20

Answer 1

$\frac{23x}{20}+4x-\frac{13x}{15}=\frac{7x}{5}+\frac{4x-5}{20}$
$\frac{23x}{20}\cdot \:60+4x\cdot \:60-\frac{13x}{15}\cdot \:60=\frac{7x}{5}\cdot \:60+\frac{4x-5}{20}\cdot \:60$
$69x+240x-52x=84x+3\left(4x-5\right)$
$257x=84x+3\left(4x-5\right)$
$257x=84x+12x-15$
$257x=96x-15$
$257x-96x=96x-15-96x$
$161x=-15$
$\frac{161x}{161}=\frac{-15}{161}$
$x=-\frac{15}{161}$