Question

20 binomios con termino común
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Answer 1

Respuesta:

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10 Ejemplos de binomios con término común

(x + 1)(x + 2) = x2 + (1+2)x + (1*2) = x2 + 3x + 2

(x + a)(x + 4) = x2 + (a+4)x + 4a

(x2 + 3)(x2 + 6) = x4 + (3+6)x2 + (3*6) = x4 + 9x2 + 18

(a + 5)(a – 8) = a2 + (5-8)a – (5*8) = a2 – 3a – 40

(y + 3)(y – 5) = y2 + (3 – 5)y + (3*-5) = y2 – 2y – 15

(b + 2)(b – 10) = b2 + (2 – 10)b + (2*-10) = b2 – 8b – 20

(x + 7)(x – 2) = x2 + (7 – 2)x + (7*-2) = x2 – 14x – 14

(xy + 1)(xy – 2) = x2y2 + (1 – 2)xy + (1*-2) = x2y2 – xy – 2

(wx + 4)(wx + 6) = w2x2 + (4 + 6)wx + (6*4) = w2x2 + 10wx + 24

(a + 1)(a – 2) = a2 + (1 – 2)a + (1*-2) = a2 – a – 2

Explicación paso a paso:

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Answer 2

Respuesta:

(y + 3)(y – 5) = y2 + (3 – 5)y + (3*-5) = y2 – 2y – 15

(b + 2)(b – 10) = b2 + (2 – 10)b + (2*-10) = b2 – 8b – 20

(x + 7)(x – 2) = x2 + (7 – 2)x + (7*-2) = x2 – 14x – 14

(xy + 1)(xy – 2) = x2y2 + (1 – 2)xy + (1*-2) = x2y2 – xy – 2

(wx + 4)(wx + 6) = w2x2 + (4 + 6)wx + (6*4) = w2x2 + 10wx + 24

(a + 1)(a – 2) = a2 + (1 – 2)a + (1*-2) = a2 – a – 2

Explicación paso a paso:

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