Question

2
(3x2 - 2y)-
$(3 {x}^{2} - 2 {y} {)}^{2}$
​

Answer 1

=(3x^2+−2y)(3x^2+−2y)

=(3x^2)(3x^2)+(3x^2)(−2y)+(−2y)(3x^2)+(−2y)(−2y)

=9x^4−6x^2y−6x^2y+4y^2

=9x^4−12x^2y+4y^2