Question

1936= 16n+n(n-1) 7
Ayudenme es progrecion aritmetica por favor!!

Answer 1

Respuesta:

$n=\frac{-121}{7} o n=16$ ojala te ayude

Explicación paso a paso:

$1936=16n+n(n-1)7\\1936=16n+7n(n-1)\\1936=16n+7n^{2} -7n\\1936=9n+7n^{2} \\1936-9n-7n^{2} =0\\-1936+9n+7n^{2}=0\\ 7n^{2} +9n-1936=0\\7n^{2}+121n-112n-1936=0\\ n(7n+121)-16(7n+121)=0\\(7n+121)(n-16)=0\\7n+121=0\\n-6=0\\n=-\frac{121}{7} 0 n=16$