Question

1. resuelve las siguientes sustracciones
a. 8/9-3/10 b. -3/5-1/3 c. 8/15-(-5/12 d. (-4/9)-(5/18) e. 3/4-(-7/3) f. 7/2-(-9/4)
porfavor con su procedimiento

Answer 1

a)8/9-3/10=

80-27/90 =

53/90 R//

b) -3/5 -1/3

-9-5/15

-14/15 R//

c) 8/15-(-5/12)

8/15 +5/12

96+75/180=

171/180 simplificando la expresion queda

19/20 R//

d) (-4/9)-5/18

-8-5/18

-13/18R//

e) 3/4-(-7/3)

9+28/12

37/12 R//

f)7/2-(-9/4)

14+9/4

23/4 R//

ahi estan todas las respuestas

Answer 2

Respuesta:

\frac{8}{9} - \frac{3}{10} = \frac{90:9.8-90:10.3}{90} = \frac{80-27}{90} = \frac{53}{90}

\frac{-3}{5} - \frac{1}{3} = \frac{15:5.(-3)-15:3.1}{15} = \frac{-9-5}{15} = \frac{-14}{15}

\frac{8}{15} - (-\frac{5}{12}) = \frac{8}{15} + \frac{5}{12} = \frac{60:15.8+60:12.5}{60} = \frac{32+25}{60} = \frac{57}{60}

\frac{-4}{9} - ( -\frac{5}{18}) = \frac{-4}{9} + \frac{5}{18} = \frac{18:9.(-4)+18:18.5}{18} = \frac{-8+5}{18} = \frac{-3}{18} = \frac{-1}{6}

\frac{3}{4} - (- \frac{7}{3}) = \frac{3}{4} + \frac{7}{3} = \frac{12:4.3+12:3.7}{12} = \frac{9+28}{12} = \frac{37}{12}= 3\frac{1}{12}

\frac{7}{2} - (-\frac{9}{4})= \frac{7}{2} + \frac{9}{4} = \frac{4:2.7+4:4.9}{4} = \frac{14+9}{4} = \frac{23}{4} = 5\frac{3}{4}