Question

(y-5)
${?}^{2}$
= y(y-8) + 11​

Answer 1

Respuesta:

y=7

Explicación paso a paso:

$(y-5)\right)^2=y\left(y-8\right)+11$

Realizamos la formula de binomio al cuadrado:$(a-b)\right)^2=a^2-2ab+b^2$

$y^2-2y\cdot \:5+5^2=y(y-8)+11\\\\y^2-10y+25=y^2-8y+11\\\\y^2-10y=y^2-8y+11-25\\\\y^2-10y=y^2-8y-14\\\\y^2-y^2-10y=-8y-14$

Ahora se van las: $y^2$

$-10y=-8y-14\\\\-10y+8y=-14\\\\-2y=-14\\\\y=7$