Question

(y + 4)2 =(4-y)(4+y)

Answer 1

Se aplica la propiedad asociativa de la suma para la simplificación de los factores.

Answer 2

Respuesta:

(y+4)² = ((4-y)(4+y))

(y)²+2(y)(4)+(4)² = (4)²-(y)²

y²+8y+16 = 16-y²

y²+8y+16-16 = 16-y²-16

y²+8y = -y²

y²+8y+y² = -y²+y²

(1+1)y²+8y = 0

2y²+8y = 0

(2y²+8y)/2 = 0/2

(2/2)y²+(8/2)y = 0

y²+4y = 0

y(y+4) = 0

y1 = 0 e y2 = - 4

Verificación con " y1 = 0 " :

((0)+4)² = (4-(0))(4+(0))

(0+4)² = (4)(4)

(4)² = 16

16 = 16

Verificación con " y2 = - 4 " :

(-4+(4))² = (4-(-4))(4+(-4))

(0)² = (4+4)(4-4)

0 = 8(0)

0 = 0

R// Por ende , " y1 = 0 " e " y2 = -4 " son las raíces o soluciones de la ecuación de segundo grado " (y+4)² = (4-y)(4+y) " .