Matemáticas, pregunta formulada por andresemiliano42, hace 23 días

y = −(3+8×5)−[0.5+0.75−(5−6)˄2]

porfa ayuda

Respuestas a la pregunta

Contestado por rosmeryquispezzz
2

Respuesta:

hola

Explicación paso a paso:

a2-a1=1,75-3=-1,25

a3-a2=0,5-1,75=-1,25

a4-a3=-0,75-0,5=-1,25

a1=3 (this is the 1st member)

an=-0,75 (this is the last/nth member)

d=-1,25 (this is the difference between consecutive members)

n=4 (this is the number of members)

3+1,75+0,5+-0,75

n(a1+an)

2

4(3+-0,75)

2

The sum of the 4 members of this series is 4,5

This series corresponds to the following straight line y=-1,25x+3

a1 =a1+(n-1)*d =3+(1-1)*-1,25 =3

a2 =a1+(n-1)*d =3+(2-1)*-1,25 =1,8

a3 =a1+(n-1)*d =3+(3-1)*-1,25 =0,5

a4 =a1+(n-1)*d =3+(4-1)*-1,25 =-0,8

a5 =a1+(n-1)*d =3+(5-1)*-1,25 =-2

a6 =a1+(n-1)*d =3+(6-1)*-1,25 =-3,2

a7 =a1+(n-1)*d =3+(7-1)*-1,25 =-4,5

a8 =a1+(n-1)*d =3+(8-1)*-1,25 =-5,8

a9 =a1+(n-1)*d =3+(9-1)*-1,25 =-7

a10 =a1+(n-1)*d =3+(10-1)*-1,25 =-8,2

a11 =a1+(n-1)*d =3+(11-1)*-1,25 =-9,5

a12 =a1+(n-1)*d =3+(12-1)*-1,25 =-10,8

a13 =a1+(n-1)*d =3+(13-1)*-1,25 =-12

a14 =a1+(n-1)*d =3+(14-1)*-1,25 =-13,2

a15 =a1+(n-1)*d =3+(15-1)*-1,25 =-14,5

a16 =a1+(n-1)*d =3+(16-1)*-1,25 =-15,8

a17 =a1+(n-1)*d =3+(17-1)*-1,25 =-17

a18 =a1+(n-1)*d =3+(18-1)*-1,25 =-18,2

a19 =a1+(n-1)*d =3+(19-1)*-1,25 =-19,5

a20 =a1+(n-1)*d =3+(20-1)*-1,25 =-20,8

a21 =a1+(n-1)*d =3+(21-1)*-1,25 =-22

a22 =a1+(n-1)*d =3+(22-1)*-1,25 =-23,2

a23 =a1+(n-1)*d =3+(23-1)*-1,25 =-24,5

a24 =a1+(n-1)*d =3+(24-1)*-1,25 =-25,8

a25 =a1+(n-1)*d =3+(25-1)*-1,25 =-27

a26 =a1+(n-1)*d =3+(26-1)*-1,25 =-28,2

a27 =a1+(n-1)*d =3+(27-1)*-1,25 =-29,5

a28 =a1+(n-1)*d =3+(28-1)*-1,25 =-30,8

a29 =a1+(n-1)*d =3+(29-1)*-1,25 =-32

coronita Pliz mucho trabajo ️️

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