Question

xd.............................................

Answer 1

Respuesta:

b . creo.

Answer 2

Respuesta:

$\log _4\left(a+2\right)\log _{10}\left(2\right)=1\quad :\quad a=4^{\frac{1}{\log _{10}\left(2\right)}}-2\quad \left(\mathrm{Decimal}:\quad a=98\right)$

Explicación paso a paso:

$\log _4\left(a+2\right)\log _{10}\left(2\right)=1$

$\frac{\log _4\left(a+2\right)\log _{10}\left(2\right)}{\log _{10}\left(2\right)}=\frac{1}{\log _{10}\left(2\right)}$

$\log _4\left(a+2\right)=\frac{1}{\log _{10}\left(2\right)}$

$a+2=4^{\frac{1}{\log _{10}\left(2\right)}}$

$a=4^{\frac{1}{\log _{10}\left(2\right)}}-2$

$\left(\mathrm{Decimal}:\quad a=98\right)$

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