Question

x³-4x²+x-2 por x -3
x⁶x4x⁵-2x+3 por x+ 2
(x¹⁵⁰-1) por x +2
(x¹⁶¹+1) por x-1

me pueden ayudar ​

Answer 1

• Primera:

$(x^{3}-4x^{2}+x-2)(x-3) =\\ \\ (x)(x^{3}-4x^{2}+x-2)-3(x^{3}-4x^{2}+x-2)=\\ \\ (x^{4}-4x^{3}+x^{2}-2x) +(-3x^{3}+12x^{2}-3x+6)=\\ \\ x^{4}-4x^{3}+x^{2}-2x -3x^{3}+12x^{2}-3x+6=\\ \\ x^{4}-7x^{3}+14x^{2}-5x+6$

• Segunda:

$(x^{6}+4x^{5}-2x+3)(x-2)= \\ \\ (x)(x^{6}+4x^{5}-2x+3)-2(x^{6}+4x^{5}-2x+3)= \\ \\ (x^{7}+4x^{6}-2x^{2}+3x)+(-2x^{6}-4x^{5}+4x-3)=\\ \\x^{7}+4x^{6}-2x^{2}+3x-2x^{6}-4x^{5}+4x-3\\ \\ x^{7}+2x^{6}-4x^{5}-2x^{2}+7x-3$

• Tercera:

$(x^{150}-1)(x+2)=\\ \\ (x)(x^{150}-1)+2(x^{150}-1)=\\ \\ (x^{151}-x)+(2x^{150}-2)=\\ \\ x^{151}+2x^{150}-x-2$

• Cuarta

$(x^{161}+1)(x-1) = \\ \\ (x)(x^{161}+1) -1(x^{161}+1) =\\ \\ (x^{162}+x)+(-x^{161}-1)= \\ \\ x^{162}-x^{161}+x-1$