Question

x² + y² = 6x-2y- 10=0​

Answer 1

Respuesta:

(x1, y1) = 5/4 , -5/4

(x2, y2) = 5/2 , 5/2

Explicación paso a paso:

x² + y² = 6x-2y- 10=0

${x}^{2} - {y}^{2} = 0 \\ 6x - 2y - 10 = 0$

${x}^{2} - {y}^{2} = 0 \\ x = \frac{1}{3} y + \frac{5}{3}$

$( \frac{1}{3} y + \frac{5}{3} ) - {y}^{2} = 0$

$y = - \frac{5}{4} \\ y = \frac{5}{2}$

$x = \frac{1}{3} x( - \frac{5}{4}) + \frac{5}{3} \\ y = \frac{5}{2}$

$x = \frac{1}{3} ( - \frac{5}{4} ) + \frac{5}{3} \\ x = \frac{1}{3} \times \frac{5}{2} + \frac{5}{3}$

$x = \frac{5}{4} \\ x = \frac{1}{3} \times \frac{5}{2} + \frac{5}{3} = \frac{5}{2}$

(x1, y1) = 5/4 , -5/4

(x2, y2) = 5/2 , 5/2

:)