Question

x²+x-12=0;x,=3,x²=-4​

Answer 1

x² + x - 12 = 0

x         + 4

x          - 3

4x - 3x = x

(x + 4)(x - 3) = 0

x + 4 = 0     x - 3 = 0

x =  -4       x = 3

CS = (-4; 3)

          Eternamente

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