Question

x²+(x+1)²=613 necesito averiguar x

Answer 1

x² + (x+1)² = 613

x² + x² + 2x + 1 = 613

2x² + 2x + 1 - 613  = 0

2x² + 2x - 612 = 0    diviso entre 2

x² + x - 306 = 0

x           + 18

x           - 17

(x + 18)(x -17) = 0

x + 18 = 0      x - 17 = 0

x = -18             x = 17

CS = ( -18; 17)

Eternamente axllxa