Question

x²+8x-6y+28=0
porfa urge con procedimiento​

Answer 1

Respuesta:

x2+8x−6y+28=0

(1)⋅x2+(8)⋅x+(−6y+28)=0

x=−(8)±(8)2−4⋅(−6y+28)−−−−−−−−−−−−−−−−−√2

x=−8±64−(−24y+112)−−−−−−−−−−−−−−−−√2

x=−8±24y−48−−−−−−−√2

x=−8±(2)⋅6y−12−−−−−−√2

x=(2)⋅[(−4)±6y−12−−−−−−√](2)

x1=−4+6y−12−−−−−−√

x2=−4−6y−12−−−−−−√