Question

X²-7X+3=0. ecuaciones por fórmula general​

Answer 1

Respuesta:

a=1

b=-7

c=3

$x_{1,2}= \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a}$

$x_{1,2}= \frac{ 7 \pm \sqrt{ { ( - 7)}^{2} - 4(3)} }{2} \\ x_{1,2}= \frac{ 7 \pm \sqrt{37}}{2}$

Answer 2

${x}^{2} - 7x + 3 = 0$

$a = 1 \\ b = - 7 \\ c = 3$

${x}^{2} - 7x + \frac{49}{4} - \frac{49}{4} + 3 \\ (x - \frac{7}{2} {)}^{2} - \frac{49}{4} + 3 \\ (x - \frac{7}{2} {)}^{2} - \frac{37}{4} \\ (x - \frac{7}{2} {)}^{2} - \frac{37}{4} = 0 \\ (x - \frac{7}{2} {)}^{2} = \frac{37}{4} \\ x - \frac{7}{2} = \frac{ \sqrt{37} }{ \sqrt{4} } \\ x - \frac{7}{2} = \frac{ \sqrt{37} }{ \sqrt{2} } \\ x - \frac{7}{2} = \frac{ \sqrt{37} }{2} \\ x - \frac{7}{2} = - \frac{ \sqrt{37} }{2} \\ x = \frac{ - \sqrt{37} + 7}{2} \\ \\ x = \frac{ \sqrt{37} + 7}{2} \\ \\ x = \frac{ - \sqrt{37} + 7}{2}$