Matemáticas, pregunta formulada por nosenosee27, hace 24 días

x²+5x-14=0

x²-10x+24=0

x²+8x-20=0

x²+5x+6=0

ayuden porfa​

Respuestas a la pregunta

Contestado por johnyriosrosales571
0

 {x}^{2}  + 5x - 14 = 0

(x  -  2)(x  +  7) = 0

x - 2 = 0

x = 2

x + 7 = 0

x =  - 7

 {x}^{2}  - 10x + 24 = 0

(x - 6)(x - 4) = 0

x - 6 = 0

x = 6

x - 4 = 0

x = 4

 {x}^{2}  + 8x - 20 = 0

(x - 2)(x + 10) = 0

x - 2 = 0

x = 2

x + 10 = 0

x =  - 10

 {x}^{2}  + 5x + 6 = 0

(x + 2)(x + 3) = 0

x + 2 = 0

x =  - 2

x + 3 = 0

x =  - 3

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