Question

(x2 - 4)3(x2 + 36)(x2 - 16)2(x2 + 1)<0

Answer 1

Respuesta:

x ∈ <-18,-1/2> ∪ <2,8>

Explicación paso a paso:

(2x-4)(2x+36)(2x-16)(2x+1)<0

(2x-4)(2x+36)(2x-16)<0

2x+1>0

(2x-4)(2x+36)(2x-16)>0

2x+1>0

x∈<-∞, -18>∪<2,8>

x>-1/2

2x+1>0

(2x-4)(2x+36)(2x-16)>0

x∈<-18, 2>∪<8,∞>

x>-1/2

x∈<2,8>

x ∈ <-18,-1/2>