Question

(x+4)al cuadrado=2x(5x-1)-7(x-2​)

Answer 1

$(x+4)^{2} = 2x(5x-1) - 7(x-2)$

$x^{2} +8x +16 = 10x^{2} - 2x -7x + 14$

$0 = 10x^{2} -  x^{2} -2x -7x -8x + 14-16$

$0 = 9x^{2} -17x -2$

9x               1

x                -2

-18x +x = -17x

(9x+1)(x-2) = 0

9x+1 = 0      y    x-2 = 0

9x = -1          y    x = 2

x = -1/9

CS = { (-1/9; 2) }

Eternamente.... axllxa