Question

(x+3)(x+2)-(x+7)(x-2)+(x+9)(x-4)-(x-4)(x+1)

Con resolución por favor!!! ​

Answer 1

(x+3)(x+2)-(x+7)(x-2)+(x+9)(x-4)-(x-4)(x+1)

Pasos:

1. $\mathrm{Expandir}\:\left(x+3\right)\left(x+2\right):\quad x^2+5x+6$
2. $=x^2+5x+6-\left(x+7\right)\left(x-2\right)+\left(x+9\right)\left(x-4\right)-\left(x-4\right)\left(x+1\right)$
3. $\mathrm{Expandir}\:-\left(x+7\right)\left(x-2\right):\quad -x^2-5x+14$
4. $=x^2+5x+6-x^2-5x+14+\left(x+9\right)\left(x-4\right)-\left(x-4\right)\left(x+1\right)$
5. $\mathrm{Expandir}\:\left(x+9\right)\left(x-4\right):\quad x^2+5x-36$
6. $=x^2+5x+6-x^2-5x+14+x^2+5x-36-\left(x-4\right)\left(x+1\right)$
7. $\mathrm{Expandir}\:-\left(x-4\right)\left(x+1\right):\quad -x^2+3x+4$
8. $=x^2+5x+6-x^2-5x+14+x^2+5x-36-x^2+3x+4$
9. $\mathrm{Simplificar}\:x^2+5x+6-x^2-5x+14+x^2+5x-36-x^2+3x+4:\quad 8x-12$
10. $=8x-12$

Espero te sirva, saludos desde Colombia.