Question

X^3+2x-5=0 cuáles son sus raíces

Answer 1

SOLUCIÓN

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                              $Sea\:la\:ecuaci\'on\:cuadr\'atica:\\\\\\ax^2+bx+c=0\\\\\\Por\:f\'ormula\:general\:tenemos\:que:\\\\\\\mathrm{\boxed{x_{1,2}=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}}}\\\\\\Del\:problema:\\\\\\a=1,b=2,c=-5\\\\\\ Entonces\:reemplazamos\\\\\\x_{1,2}=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x_{1,2}=\dfrac{-(2)\pm \sqrt{(2)^2-[4(1)(-5)]}}{2(1)}\\\\\\x_{1,2}=\dfrac{-2\pm \sqrt{4-(-20)}}{2}\\\\\\x_{1,2}=\dfrac{-2\pm \sqrt{24}}{2}$

                         $\Rightarrow\:\boxed{\boldsymbol{x_{1}=\dfrac{-2+2\sqrt{6}}{2}}}\\\\\\\Rightarrow\:\boxed{\boldsymbol{x_{2}=\dfrac{-2-2\sqrt{6}}{2}}}$