Question

(x−2y ^2 +3z^ 3 ) ^ 2

Answer 1

(x−2y²+3z³)2²

=(x+−2y²+3z³)(x+−2y²+3z³)

=(x)(x)+(x)(−2y²)+(x)(3z³)+(−2y²)(x)+(−2y²)(−2y²)+(−2y²)(3z³)+(3z3)(x)+(3z³)(−2y²)+(3z³)(3z³)

=x2−2xy²+3xz³−2xy²+4y4−6y²z³+3xz³−6y²z³+9z6

=9z6−12y2z³+6xz³+4y4−4xy²+x2

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