Question

(x+2)(x+4)=
(y+8)(y-4)=
(2x + 10) (2x+6)=
(3y-5) (3y + 7) =
(x-12)(x+35)=
ayudenmeeeeee​

Answer 1

Respuesta:

1. (x+2)(x+4)

• X×X+4X+2X+2×4
• ${x}^{2} + 4x + 2x + 8$
• ${x}^{2} + 6x + 8$

2. (y+8)(y-4)

• $(8y) \times (y - 4) \\ 8y \times (y - 4) \\ 8 {y}^{2} - 32y$

3. (2x + 10) (2x+6)

$2x \times 2x + 2x \times 6 + 10 \times 2x + 10 \times 6 \\ 4 {x}^{2} + 12x + 20x + 60 \\ 4 {x}^{2} + 32x + 60$

4. (3y-5) (3y + 7)

$3y \times 3y + 3y \times 7 - 5 \times 3y - 5 \times 7 \\ 9 {y}^{2} + 21y - 15y - 35 \\ 9 {y}^{2} + 6y - 35$

5. (x-12)(x+35)

$x \times x + 35x - 12x - 12 \times 35 \\ {x}^{2} + 35x - 12x - 420 \\ {x}^{2} + 23x - 420$