Question

x^2-x+1 calcular pendiente cuando x=1 x=0 y x=-1

Answer 1

Respuesta:

$Cuando \: \: x = 1 \\ {x}^{2} - x + 1 = {1}^{2} - 1 + 1 = 1 - 1 + 1 = 1$

$Cuando \: \: x = 0 \\ {x}^{2} - x + 1 = {0}^{2} - 0 + 1 = 0 - 0 + 1 = 1$

$Cuando \: \:x = - 1 \\ {x}^{2} - x + 1 = {( - 1)}^{2} - ( - 1) + 1 = 1 + 1 + 1 = 3$