(x – 2)2 = x 2
m) 3 · (2x – 6) – [(x – (3x – 8) + 2) – 1] = 2 – (3 – 2x)
n) (x – 2)2 = x
2
ñ) x · (x + 4) = x
2 + 8
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1) (x-2)²= x²
(x-2)(x-2)= x²
x²-2x-2x+4 = x²
-4x+4=0
-4x = -4
x = -4/-4
x=1
2) 3(2x-6)-[(x-(3x-8)+2)-1]=2-(3-2x)
6x-18-[x-3x+8+2-1] = 2-3+2x
6x-18-[-2x +9] = -1 +2x
6x -18 +2x -9 = -1+2x
8x - 27 = -1+2x
8x -2x =-1+27
6x = 26
x = 26/6
x = 13/2
(x-2)(x-2)= x²
x²-2x-2x+4 = x²
-4x+4=0
-4x = -4
x = -4/-4
x=1
2) 3(2x-6)-[(x-(3x-8)+2)-1]=2-(3-2x)
6x-18-[x-3x+8+2-1] = 2-3+2x
6x-18-[-2x +9] = -1 +2x
6x -18 +2x -9 = -1+2x
8x - 27 = -1+2x
8x -2x =-1+27
6x = 26
x = 26/6
x = 13/2
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