Question

(x - 2)^2 - (3-x)^2 al cuadrado = 1

Answer 1

Solución

Resolver:

$\large\boxed {\bold {(x-2)^{2} - (3-x)^{2} =1 }}$

$\boxed {\bold {(x-2)^{2} - (3-x)^{2} -1 = 0 }}$

$\boxed {\bold { x^{2} -4x+4-9+6x-x^{2} -1 = 0 }}$

$\boxed {\bold { \not x^{2} -4x+4-9+6x-\not x^{2} -1 = 0 }}$

$\boxed {\bold { -4x+4-9+6x -1 = 0 }}$

$\boxed {\bold { -4x+6x+4-9 -1 = 0 }}$

$\boxed {\bold { 2x+4-9 -1 = 0 }}$

$\boxed {\bold { 2x+4-10= 0 }}$

$\boxed {\bold { 2x -6= 0 }}$

$\boxed {\bold { 2(x -3)= 0 }}$

$\boxed {\bold { \frac{ \not 2(x -3) }{\not 2} = \frac{0}{2} }}$

$\boxed {\bold { x -3= 0 }}$

$\large\boxed {\bold { x= 3}}$