Question

(x-2)²/16 (y+4)²/7 =1
coordenada del centro (h,k)
Porfavor ​

Answer 1

Respuesta:

holui y garacias por los puntos la corona plis

Answer 2

Respuesta:

(x-2)²/16 (y+4)²/7 =1

coordenada del centro (h,k)

Porfavor

Explicación paso a paso:

$\frac{\left(x-2\right)^2}{16}\cdot \frac{\left(y+4\right)^2}{7}=1\\\\\frac{\left(x-2\right)^2\left(y+4\right)^2}{16\cdot \:7}=1\\\\\frac{\left(x-2\right)^2\left(y+4\right)^2}{112}=1\\\\\frac{112\left(x-2\right)^2\left(y+4\right)^2}{112}=1\cdot \:112$

$\left(x-2\right)^2\left(y+4\right)^2=112\\\\\frac{\left(x-2\right)^2\left(y+4\right)^2}{\left(y+4\right)^2}=\frac{112}{\left(y+4\right)^2};\quad \:y\ne \:-4\\\\\left(x-2\right)^2=\frac{112}{\left(y+4\right)^2};\quad \:y\ne \:-4$

$x=\frac{4\sqrt{7}}{y+4}+2,\:x=-\frac{4\sqrt{7}}{y+4}+2;\quad \:y\ne \:-4$