Question

x^{2} -16x-80 porfabor

Answer 1

Respuesta:

$x_{1} =20$

$x_{2} = -4$

Explicación paso a paso:

$x^{2}-16x-80=0$

utilizamos la ecuación general de las cuadraticas

$x_{1} = \frac{-(-16)+\sqrt{16^{2}-4(1)(-80) } }{2(1)}$

$x_{1} = \frac{16+\sqrt{256+320} }{2}$

$x_{1} = \frac{16+\sqrt{576} }{2}$

$x_{1} = \frac{16+24 }{2}$

$x_{1} = \frac{40 }{2}$

$x_{1} =20$

$x_{2} = \frac{-(-16)-\sqrt{16^{2}-4(1)(-80) } }{2(1)}$

$x_{2} = \frac{16-\sqrt{256+320} }{2}$

$x_{2} = \frac{16-24 }{2}$

$x_{2} = \frac{-8 }{2}$

$x_{2} = -4$