Question

(x + 10)(x-10)=
(x+9) (9-x) =
(x+4)(x-4)=
. (x+5)(x-5)=
(3a + 3b) (3a - 3b) =
(10-5) (10 + 5) =
(a + b)(a - b) =
(x + 14)(x - 14) =
2.- (x+7)(x-7)=
_ (x+9)(x-9)=_
(x+3)(x-3)=
(-4x+3y)(+4x+3y) =
__ (5x + 2)(5x – 2) =
(10+ 1)(10-1) =
(100+ 1)(100-1) =
. (y-12) (y +12)=
(3m+2n)(3m-2n) =
_ (4xy-2x)(4xy + 2x)=
(5x + 8)(5x – 8) =
(4y-5x)(4y+5x) =​

Answer 1

Respuesta:

x² - 100

x² + 81

x²- 16

x² ‐ 25

9a² + 9b²

75

a² - b²

x² + 14x

2x² - 98

-x² +81

x² ‐ 9

-16x² + 9y²

-25x² + 4

100 -10 +100-1 =181

y² -144

9m² - 4n²

16xy² + 4x²

25x² - 64

16y² -25x²