Question

(x+1) + (x-2) : (x+2) + (x-1) TODOS LOS PARENTESIS ELEVADOS AL CUADRADO

Answer 1

$(x+1)^{2} + (x-2)^{2} = (x+2)^{2} + (x-1)^{2} (x^{2} + 2x + 1) + (x^{2} - 4x + 4) = (x^{2} + 4x + 4) + (x^{2} - 2x + 1) 2x^{2} - 2x^{2} + 2x - 2x + 5 - 5 = 0 0 = 0$