Question

(x+1)^2+(2x+3)^2+6=8
(x+2)(x-2)-7(x-1)=21
UwU

Answer 1

Respuesta:

(x+1)^2+(2x+3)^2+6=8

x^ 2+2x+1 + 4x^ 2+12x+9+6=85

x^ 2+14x+17=8  

5x^ 2+14x+9=0

(5x+9)(x+1)=0

x=-9/5

x=-1 

(x+2)(x-2)-7(x-1)=21  

x^2 - 4 - 7x +7=21

x^2 - 7x -18=0

(x+2)(x-9)=0

x=-2

x=9

Explicación paso a paso: