Question

what is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?

Answer 1

Hi!

 

The distance around a triangle, better noun as de "perimeter of a triangle"

is the total distance around the outside, which can be found by adding together the length of each side.

 

Perimeter (P) = Length A + Length B + Lenght C

 

In this case, we know that each side measure 2 $\frac{1}{8}$ feet, 3 $\frac{1}{2}$ feet, and 2 $\frac{1}{2}$ feet  but we have to rewrite each one of this mixed fractions as improper fractions:

2 $\frac{1}{8}$ = $\frac{16 + 1}{8}$ = $\frac{17}{8}$  

3 $\frac{1}{2}$ = $\frac{6 + 1}{2}$ = $\frac{7}{2}$

2 $\frac{1}{2}$ = $\frac{4 + 1}{2}$ = $\frac{5}{2}$

 

Then we just add all of them to find the perimeter:

$\frac{17}{8} +  \frac{7}{2} + \frac{5}{2}$ = $\frac{17 + 28 + 20}{8}$ = $\frac{65}{8}$

A: The distance around a triangle is $\frac{65}{8}$ feet