Question

Valor numérico
1. Si f(x)= 3x 2 + 8, hallar f(4) – f(-1)
2. Si f(x) = 2x –1; g(x) = 3x +2;
halle: f(2) + g(5) – 1

Answer 1

Respuesta:

1. Si f(x)= 3x2 + 8,  hallar f(4) – f(-1) = 56 - 11 = 45

2. Si f(x) = 2x –1, g(x) = 3x +2,     halle: f(2) + g(5) – 1 = 3+17-1 = 19

Explicación paso a paso:

1. Si f(x)= 3x2 + 8

f(4) = 3(4)²+8 = 3(16)+8 = 48+8=56

f(-1) = 3(-1)²+8 = 3(1)+8 = 3+8 = 11  

hallar f(4) – f(-1) = 56 - 11 = 45

2. Si f(x) = 2x –1

f(2) = 2(2) - 1 = 4 - 1 =3

g(x) = 3x +2

g(5) = 3(5)+2 = 15+2 = 17  

halle: f(2) + g(5) – 1 = 3+17-1 = 19