Question

Utilizar el teorema del seno y del coseno para resolver el triángulo:
A=60° B= 45° a=10cm c=12cm

Answer 1

B
${b}^{2} = {a}^{2} + {c}^{2} - 2ac \cos(b)$
${b}^{2} = {10}^{2} + {12}^{2} - 2(10)(12)( \cos(45))$
$b \sqrt{100} + 144 - 240 \cos(45)$
$b = \sqrt{244} - 240 \cos(0.7071067812)$

b=√74.29
b=8.61