Question

usando regla de la cadena f(x)=(√x+1) ³​

Answer 1

$\\\sqrt{x} = x^{\frac{1}{2} } \\\f'(x)=3(\sqrt{x} +1)^{2} (\frac{1}{2} x^{\frac{-1}{2} }\\ \\ f'(x)=3(\sqrt{x} +1)^{2} (\frac{1}{2\sqrt{x} } \\\\f'(x)=\frac{3(\sqrt{x} +1)^{2}}{2\sqrt{x} }}$

Listo :D