Question

urgente¡¡¡¡¡¡¡¡¡¡ y le doy 40

Answer 1

Respuesta:

Pitágoras en ABC

$15^{2} =5^{2} +x^{2}$

$200=x^{2}$

$10\sqrt[]{2} =x$

$L=\frac{15}{10\sqrt[]{2} } +\frac{5}{10\sqrt[]{2} }$

$L=\frac{20}{10\sqrt[]{2} }$

$L=\sqrt[]{2\\}$