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Como hago este ejercicio? Ayuda la respuesta es - 359
Respuestas a la pregunta
Considerando que la nitroglicerina se descompone según la siguiente ecuación:
4C3H5(NO3)3 → 12CO2 + 10 H2O + O2 + 6N2 ΔHº = - 5700 Kj
ΔHfº [CO2(g)] = −393,5 kJ/mol; ΔHfº [H2O(g)] = −241,8 kJ/mol
Cuál es el calor de formación estándar en Kj de la nitroglicerina
calcular ΔHnitroglicerina = ?
4 ΔHfº C3H5(NO3)3 = 12ΔHfºCO2 + 10 ΔHfºH2O + ΔHfºO2 + 6ΔHfºN2
( ΔHfºO2) = 0 / ( 6ΔHfºN2 ) = 0
quedando:
ΔHfº C3H5(NO3)3 = 12ΔHfºCO2 + 10 ΔHfºH2O - (-5700 kj)
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4
sustituir:
ΔHfºC3H5(NO3)3 = 12(−393,5 kJ/mol)CO2+10(−241,8 kJ/mol)H2O -(-5700 kj)
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4
ΔHfºC3H5(NO3)3 = -4722 Kj/mol - 2418 KJ/mol + 5700 KJ
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4
ΔHfºC3H5(NO3)3 = 360 Kj