Question

URGENTE :( ¿PUEDEN AYUDARME A RESOLVER?

Answer 1

$f(x)=3x+2, \quad g(x)= \frac{x+3}{2x+1} \\ g o f(x) = \frac{(3x+2)+3}{2(3x+2)+1}=\frac{3x+5}{6x+5} \\ f o g(x) = 3(\frac{x+3}{2x+1})+2 = \frac{3x+9}{2x+1}+2 = \frac{3x+9}{2x+1}+\frac{4x+2}{2x+1}=\frac{7x+11}{2x+1}\\ g o f(2) = \frac{3(2)+5}{6(2)+5} = \frac{11}{17}\\ f o g(-3) = \frac{7(-3)+11}{2(-3)+1} = \frac{10}{5}=2$