Question

Urgente....Extraer a factor comun...(A) 5x²-5y. (B)3ab+2a. (C)4x²-8x. (D)5ab+6ac -3ac. (E)3a-9a. (F)3z³-2z²

Answer 1

A)5(x²-y) B)a(3b+2) C)2x(2x-4) D)a(5b+6c-3c) E)3a(1-3) F)z²(3z-2)

Answer 2

Factorizar.

Caso.
Factor comun.
5x² - 5y =    Sacas factor comun 5
5(x² - y)

3ab + 2a =    Sacas factor comun a
a(3b + 2)


4x² - 8x =    Sacas factor comu 4x
4x(x - 2)


5ab + 6ac - 3ac  =  Sacas factor comun a
a(5b + 6c - 3c) =
a(5b + 3c)


3a - 9a 0  Sacas factor comun 3a
3a(1 - 3)
3a(- 2)


3z³ - 2z² =  Sacas factor comun z²
z²(3z - 2)